If z is a standard normal variable, find the probability.P(–0.73 < z < 2.27) 0.2211 0.4884 1.54 0.7557

Answer:0.7557Step-by-step explanation:In this question use the Table of Standard Normal Probabilities for Negative z-scores and the Table of Standard Normal Probabilities for Positive z-scoresWhere z=2.27 NORMDIST(2.27)=0.9884 (read from table for positive z-scores)Where z=-0.73 NORMDIST(-0.73)=0.2327 (read from table for negative z-scores)You know P(-0.73<z<2.27)= 0.9884-0.2327=0.7557